Answer:
Explanation:
To find the weight (W) of the pond contents first we need to use the following equation:
(1)
Where m the mass and g is the gravity
Also, we have that the mass is:
(2)
Where ρ is the density and V the volume
We cand calculate the volume as follows:
(3)
Where L is the length, w is the wide and d is the depth
By entering equation (2) and (3) into (1) we have:
Therefore, the weight of the pond is 6.65x10⁶ lbf.
I hope it helps you!
A mole of any gas occupied 22.4 L at STP. So, the number of moles of nitrogen gas at STP in 846 L would be 846/22.4 = 37.8 moles of nitrogen gas.
Alternatively, you can go the long route and use the ideal gas law to solve for the number of moles of nitrogen given STP conditions (273 K and 1.00 atm). From PV = nRT, we can get n = PV/RT. Plugging in our values, and using 0.08206 L•atm/K•mol as our gas constant, R, we get n = (1.00)(846)/(0.08206)(273) = 37.8 moles, which confirms our answer.
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Answer:
go to a calculator and see the answer then make the hypothisis which is the answer
Explanation:
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Answer:
It’s b even check quizzes
Explanation: