Y = mx + b, where m = slope = rise/run and b, the y intercept value
m = 1/1 = 1, then y = x + b.
We notice that y intercept is = - 1
And the equation is:
y = x - 1
Answer:
The first option is the correct one, the area of the shaded portion of the circle is
[/tex](5 \pi -11.6)ft^2[/tex]
Step-by-step explanation:
Let us first consider the triangle + the shadow.
The full area of the circle is the radius squared times pi, so
A=
Since , the area of the triangle + the shaded area is one fifth of the area of the whole circle, thus
If we want to know the area of the shaded part of the circle, we must subtract the area of the triangle from .
The area of the triangle is given by
Thus the area of the shaded portion of the circle is
Answer:
Step-by-step explanation:
line of reflection: <em>a fixed line directly in the middle of the pre-image and the reflected image. </em>
perpendicular: <em>two lines meeting at a 90 degree angle</em>
bisector: <em>line that divides something into two equal parts</em>
pre-image: <em>the original figure before any transformation or translation has been made</em>
reflected image: <em>the original image after being reflected across the line of reflection.</em>
<em />
Is the line of reflection a line running perpendicular, directly in the middle of the pre-image and the reflected image? Yes, always would be my answer.
Answer:
pH can be different from 7 ( second statement is false)
Step-by-step explanation:
since
pH=pKa + log [A-]/[HA]
at half of the equivalence point
[HA]= [A-] (third statement is true)
and therefore
pH = pKa (first statement is true)
since pH = pKa , pH can be different from 7 ( second statement is false)
<h2>Answer: (n^3)/(Q-r)=h</h2>
Factor out h and then divide each side by (Q-r) and you get the answer :) I hope this helped