Answer:
Limiting reactant: O2
grams NO2 produced = 230.276 g NO2
grams of NO unused = 26.67 gNO
Explanation:
2NO + O2 --> 2NO2
Step 1: Determine the molar ratio NO:O2
molar ratio NO:O2 = 5.895: 2.503 = 2.35
stoichiometric molar ratio NO:O2 = 2:1
So, O2 is the limiting reactant.
Step2: Determine the grams of NO2:
?g NO2 = moles O2 x (2moles NO2/1 mol O2) x (MM NO2/ 1 mol NO2) = 2.503 x 2 x 46 = 230.276 g NO2
Step 3: Determine the amount of excess reagent unreacted
moles excess NO reacted = moles O2 x (2 moles NO/1 mol O2) = 2.503 x 2 = 5.006 moles NO reacted
moles NO unreacted = total moles NO - moles NO reacted = 5.895-5.006 =0.889 moles NO unreacted
mass NO unreacted = moles NO unreacted x MM NO = 0.889 x 30 =26.67 g NO unreacted
Answer:
light energy to convert carbon dioxide and water into glucose and oxygen gas. Each molecule of glucose essentially “stores” up to 38 molecules of ATP which can be broken down and used during other cellular reactions.
Explanation:
According to your equation, for every mole of iron oxide (Fe2O3), it takes 3 moles of carbon monoxide (CO). So for 1.75 moles, it takes 3 times as many moles of CO.
1.75 x 3 = 5.25 moles of CO.
I think your product is CO2. Dalton's Law sayeth that the coefficients tell us the ratios of moles. So if you hve 1.75 moles of Fe(III)oxide, 3*1.75 moles of CO are needed (in theory) to react completely. The answer is requested in moles, so you need go no further.