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2 years ago

SOMEBODYY HELP ILL GIVE BRAINLYY......

Mathematics

1 answer:

ANTONII [103]2 years ago

3 0

Step-by-step explanation:

a^2+b^2 = c^2

C is the biggest number, so put in all the numbers in the equation then if it's equal then it's a right triangle.

example: 6^2 + 8^2 = 10^2

36 + 64 = 100

100 = 100

this one is a right angle because the two sides is equal to the hypotenuse(largest number).

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Please help, it is due tonight!

PolarNik [594]

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4 0

1 year ago

Read 2 more answers

Which is equivalent to this expression? 2/150 + 3/75

Lesechka [4]

Answer:

Step-by-step explanation:

$\frac{2}{150}$ First reduce this to lowest term

$\frac{2}{150}=\frac{1}{75}\\\\\frac{2}{150}+\frac{3}{75}=\frac{1}{75}+\frac{3}{75}\\\\=\frac{1+3}{75}=\frac{4}{75}\\$

7 0

2 years ago

Help plsss Show me the work plsss

velikii [3]

Answer:

a) y = 6x - 3

b) 1/3y = 2x -1

The first thing you need to do is isolate (y) in the second equation

3 x (1/3y) = 3 x (2x - 1)

y =6x - 3

After isolating (y) in equation b they end up being the same.

Graphing:

In order to graph this, you have to make the first point at (0, -3) since this is the Y-intercept of the equation.

In order to graph the other points, you must move 6 units up and 1 unit to the right. Or vise versa If you need a visual I'll gladly link one.

5 0

2 years ago

Write down the explicit solution for each of the following: a) x’=t–sin(t); x(0)=1

Kay [80]

Answer:

a) x=(t^2)/2+cos(t), b) x=2+3e^(-2t), c) x=(1/2)sin(2t)

Step-by-step explanation:

Let's solve by separating variables:

$x'=\frac{dx}{dt}$

a) x’=t–sin(t), x(0)=1

$dx=(t-sint)dt$

Apply integral both sides:

$\int {} \, dx=\int {(t-sint)} \, dt\\\\x=\frac{t^2}{2}+cost +k$

where k is a constant due to integration. With x(0)=1, substitute:

$1=0+cos0+k\\\\1=1+k\\k=0$

Finally:

$x=\frac{t^2}{2} +cos(t)$

b) x’+2x=4; x(0)=5

$dx=(4-2x)dt\\\\\frac{dx}{4-2x}=dt \\\\\int {\frac{dx}{4-2x}}= \int {dt}\\$

Completing the integral:

$-\frac{1}{2} \int{\frac{(-2)dx}{4-2x}}= \int {dt}$

Solving the operator:

$-\frac{1}{2}ln(4-2x)=t+k$

Using algebra, it becomes explicit:

$x=2+ke^{-2t}$

With x(0)=5, substitute:

$5=2+ke^{-2(0)}=2+k(1)\\\\k=3$

Finally:

$x=2+3e^{-2t}$

c) x’’+4x=0; x(0)=0; x’(0)=1

Let $x=e^{mt}$ be the solution for the equation, then:

$x'=me^{mt}\\x''=m^{2}e^{mt}$

Substituting these equations in c)

$m^{2}e^{mt}+4(e^{mt})=0\\\\m^{2}+4=0\\\\m^{2}=-4\\\\m=2i$

This becomes the solution m=α±βi where α=0 and β=2

$x=e^{\alpha t}[Asin\beta t+Bcos\beta t]\\\\x=e^{0}[Asin((2)t)+Bcos((2)t)]\\\\x=Asin((2)t)+Bcos((2)t)$

Where A and B are constants. With x(0)=0; x’(0)=1:

$x=Asin(2t)+Bcos(2t)\\\\x'=2Acos(2t)-2Bsin(2t)\\\\0=Asin(2(0))+Bcos(2(0))\\\\0=0+B(1)\\\\B=0\\\\1=2Acos(2(0))\\\\1=2A\\\\A=\frac{1}{2}$

Finally:

$x=\frac{1}{2} sin(2t)$

7 0

2 years ago

dwight can drive 60 miles for each gallon of gas on his motorcycle how far can dwight go if he has 3 gallons of gas

Aleksandr-060686 [28]

Answer:

180

Step-by-step explanation: 60+60 =120 120+6

5 0

2 years ago