First, let us restate the given conditions
c is 5 more than variable a ( c = a + 5)
c is also three less than variable a (c = a - 3)
Now, lets look at the answer choices and or given
c = a − 5
c = a + 3
Here, c is 5 less than "a"...so automatically disqualified
a = c + 5
a = 3c − 3
Here, we have to get "C" by itself in both top and bottom equation.
So,
Simplified version :
c = a - 5
Here, c is 5 less than "a"...so automatically disqualified
a = c − 5
a = 3c + 3
Here also, we have to get "C" by itself in both top and bottom equation.
So,
simplified version:
c = a + 5
Here, c is 5 more than "a"...so we continue
c = (a - 3) / 3
Here, c is 3 less than "a" <u>divided by 3</u><u /> . So, this is not correct
c = a + 5
c = a − 3
Here, c is 5 more than "A"
Also, c is 3 less than "a"
Which satisfies the given.
So, our answer is going to be the last one:
c = a + 5
c = a - 3
4.428571
I know because I googled it
He probably didnt get diabetes
Answer: 4(5+2) or 4(2+5)
Step-by-step explanation:
8 = 2*2*2
20 = 2*2*5
4(5+2) = 20+8
Answer:
Approximately 18 units will be produced before the output rate exceeds 12 units per hour.
Step-by-step explanation:
The learning curve formula is given by:
In which:
Y is the average time per unit.
X is the cumulative number of units produced.
a is the time required to produe the first unit
b = log of learning rate/log 2
In our problem, we have:
Y = 12 units per hour. We are working in minutes, what is the average time per unit?
60 minutes - 12 units
Y minutes - 1 unit
So Y = 5.
X is the value we want to find
a = 30
b = 
So
![\sqrt[0.6215]{X^{0.6215}} = \sqrt[0.6215]{6}](https://tex.z-dn.net/?f=%5Csqrt%5B0.6215%5D%7BX%5E%7B0.6215%7D%7D%20%3D%20%5Csqrt%5B0.6215%5D%7B6%7D)
Approximately 18 units will be produced before the output rate exceeds 12 units per hour.
