Answer:
<h3><u>Cylinder</u></h3>
Given:
<h3><u>Cube</u></h3>
Given:
<h3><u>Volume available to be filled with water</u></h3>
Volume of cylinder - volume of cube
= 684π - 512
= 1532.75204 cm³
1 litre = 1000 cm³
⇒ 1.5 litres = 1000 × 1.5 = 1500 cm³
As 1500 < 1532.75204, the volume of water poured into the container is smaller than the empty space available in the cylinder. Therefore, the water will <u>not</u> come over the top of the container.
C is 2020 bdecuase I want points
H = 151t - 16t²
The height of the ball when it return to the ground will be 0
0 = 151t - 16t²
The zero product property is that when two numbers are being multiplied and the product is 0, one of them must be equal to 0. Therefore, we can factorize this equation:
16t² - 151t = 0
t(16t - 151t) = 0
By the zero product property:
t = 0 or 16t - 151 = 0
So t = 0 or t = 9.44 seconds
The first solution is before he releases the ball and the second is when the ball comes back to the ground. Thus, the ball's air time is 9.44 seconds.
