Obtuse: b^2 + c^2 > a^2
Right: b^2 + c^2 = a^2
Acute: b^2 + c^2 < a^2
A^2 + B^2 + c^2 - 2bc*cosA
As (A), is an Obtuse cos A is Negative say 2bccosA = - k then;
a^2 = b^2 + c^2 + k
a^2 > b^2 + c^2
So, your Answer would be (B)
Hope this helps!!.!
It has to be the last one, D. I did it over 3 times to make sure.
Answer:
The answer is 12
Step-by-step explanation:
So, first we multiply the fraction by using the formula a/b times c/d= a times c/b times d
=(y^2-16) times 5y/2y(y-4)
Now, we cancel the common factor y
=(y^2-16) times 5/2(y-4)
Now, we factor 5(y^2-16)
We factor (y^2-16) first
y^2-16
Rewrite 16 as 4^2
y^2-4^2
Now, apply the formula x^2-y^2=(x+y)(x-y)
=y^2-4^2=(y+4)(y-4)
=5(y+4)(y-4)
=5(y+4)(y-4)/2(y-4)
Cancel the common factor y-4
=5(y+4)/2
Answer: 5(y+4)/2
Answer:
B = (zx/2)+ (qx/2)
Step-by-step explanation:
