The Goldbach Conjecture is a yet unproven conjecture stating that every even integer greater than two is thesum of two prime numbers. The conjecture has been tested up to 400,000,000,000,000. Goldbach's conjecture is one of the oldest unsolved problems in number theory and in all of mathematics.
Answer:1) c. 5,9,13,17,21
2) a. a1=8, an=an-1 -2
Step-by-step explanation: 1) an=4n+1
⇒ a1=4×1+1=5
a2=4×2+1=9
a3=4×3+1=13
a4=4×4+1=17
a5=4×5+1=21
2) clearly a1=8 and then the terms of series are decreasing by 2
so, an=an-1 -2
Answer:
x = π/3, x = 5π/3, x = 4π/3
Step-by-step explanation:
Let's split the given equation (2cosx-1)(2sinx+√3 ) = 0 into two parts, and solve each separately. These parts would be 2cos(x) - 1 = 0, and 2sin(x) + √3 = 0.
Remember that the general solutions for cos(x) = 1/2 are x = π/3 + 2πn and x = 5π/3 + 2πn. In this case we are given the interval 0 ≤ x ≤2π, and therefore x = π/3, and x = 5π/3.
Similarly:
The general solutions for sin(x) = - √3/2 are x = 4π/3 + 2πn and x = 5π/3 + 2πn. Therefore x = 4π/3 and x = 5π/3 in this case.
So we have x = π/3, x = 5π/3, and x = 4π/3 as our solutions.
The answer for each large square represents 1 whole is number4
The answer is -8/15 because you need to cancel out the variables first