Answer:
(a + b)(c + d), ac+ ad+ bc + bd, 2x squared + x - 3 or (2x+ 3)(x -1).
Step-by-step explanation:
For an expression of the form (a + b)(c + d), the expanded version is ac + ad + bc + bd, in other words everything in the first bracket should be multiplied by everything in the second. Factorising is the reverse of expanding brackets, so it is, for example, putting 2x² + x - 3 into the form (2x + 3)(x - 1).
a-7=3(b+2)
1. Simplify/Combine like terms
a-7=3b+6
2. Remove a variable
a-7-a=3b+6-a
7=2b+6
3. Isolate the variable
7-6=2b-6
1=2b
4. Divide
1/2=2b/2
b=1/2
1/2g?
Answer:
24
Step-by-step explanation:
The question is saying, how many three digit numbers can be made from the digits 3, 4, 6, and 7 but there can't be two of the same digit in them. For example 346 fits the requirements, but 776 doesn't, because it has two 7s.
Okay, on to the problem:
We can do one digit at a time.
First digit:
There are 4 digits that we can choose from. (3, 4, 6, and 7)
Second digit:
No matter which digit we chose for the first digit, there is only going to be 3 of them left, because we already chose one, and you can't repeat that same digit. So there are 3 options.
Third digit:
Using the same logic, there are only 2 options left.
We have 4 choices for the first digit, 3 choices for the second, and 2 for the third.
Hence, this is 4 * 3 * 2 = 24 three-digit numbers that can be made.