Answer: He can raise up to 40 goats and 100 llamas.
Step-by-step explanation:
Hi, to answer this question we have to write system of equations with the information given:
The space each goat needs (4) multiplied by the number of goats (x); plus The space each llama needs (10) multiplied by the number of llamas must be less or equal to the acre land available (800)
4x +10y ≤ 800 (acres)
The amount of veterinary care (in $) each goat needs (110) multiplied by the number of goats (x); plus The amount of veterinary care each llama needs (88) multiplied by the number of llamas (y)must be less or equal to the Rancher's budget.(14520)
110x +88y ≤ 14,520 (cost)
Multiplying the first equation by 27.5, and subtracting the second equation to the first one:
110x + 275y ≤22,000
-
110x +88y ≤ 14,520
____________
187y ≤ 7480
y ≤ 7480/187
y ≤ 40
Replacing y in the first equation
4x +10(40) ≤ 800
4x +400 ≤ 800
4x ≤ 800-400
4x ≤ 400
x ≤ 400/4
x ≤ 100
In this equation, you have to treat the number in the bracket first on the basis of BODMAS
15 - [-3]- 4
Note that when two minuses come together the product is a plus sign.
15 +3 - 4
You have to add before you subract
18 - 4 =14
Therefore, 15- [-3] - 4 = 14.
Answer:
first number(x) = 2 second number(y)= 6
Step-by-step explanation:
This is an example of a simultaneous equation.
First write this word problem as equations, where x is the "first number" that you've mentioned and y is the "second number".
x + 2y = 14 (equation 1)
2x + y = 10 (equation 2)
This is solved using the elimination method.
We need to make one of the coefficients the same - in this case we can make y the same. In order to do this we need to multiply equation 2 by 2, so that y becomes 2y.
2x + y = 10 MULTIPLY BY 2
4x + 2y = 20 (this is now our new equation 2 with the same y coefficient)
Now subtract equation 1 from equation 2.
4x - x + 2y - 2y = 20 - 14 (2y cancels out here)
3x = 6
x = 2
Now we substitute our x value into equation 1 to find the value of y.
2 + 2y = 14
2y = 12
y = 6
Hope this has answered your question.
Given,
A sign company charges $28 per yard for each custom-made banner.
Ms.Gill orders two banners that are each 178 yards long, and one banner that is 258 yards long.
To find,
Total money paid by Ms. Gill.
Solution,
Total length of 2 banners of 178 yards = 356 yards
Third banner is 258 yards long.
Total length of the banners = 356 + 258
= 614 yards
The cost of each banner = $28 per yards.
Total amount paid by Ms. Gill is :
= $28 × 614
= $17,192
Hence, she will pay $17,192 for all the three banners.
<span>associative property of multiplication
answer
</span><span>4 ∙ (3 ∙ 6) = (4 ∙ 3) ∙ 6 </span>