Answer:
Expected number of free throws in 60 attempts:
Best player = 48
2nd best player = 45
3rd best player = 42
Step-by-step explanation:
Solution:-
- The probability that best player makes free throw, p1 = 0.8
- The probability that second-best player makes free throw, p2 = 0.75
- The probability that third-best player makes free throw, p3 = 0.70
- Total number of attempts made in free throws, n = 60.
- The estimated number of free throws that any player makes is defined by:
E ( Xi ) = n*pi
Where, Xi = Player rank
pi = Player rank probability
- Expected value for best player making the free throws would be:
E (X1) = n*p1
= 60*0.8
= 48 free throws
- Expected value for second-best player making the free throws would be:
E (X2) = n*p2
= 60*0.75
= 45 free throws
- Expected value for third-best player making the free throws would be:
E (X3) = n*p3
= 60*0.70
= 42 free throws
<span>it false ......................</span>
0.4 * x = 68
x = 68/0.4
x = 170
check:
0.4 * 170 = 68
The answer is <span>1683.
Hope this helps.</span>
Answer:
y = 1/3
Step-by-step explanation:
2/3 (6y - 4) = - 4y
2(6y-4)/3 = -4y
2(6y-4) = (-3)(4y)
y = 1/3