Answer: Conjecture: There is no triangle with side lengths N, 2N, and 3N (where N is a positive real number)
Proof:
We prove this by contradiction: Suppose there was an N for which we can construct a triangle with side lengths N, 2N, and 3N. We then apply the triangle inequalities tests. It must hold that:
N + 2N > 3N
3N > 3N
3 > 3
which is False, for any value of N. This means that the original choice of N is not possible. Since the inequality is False for any value of N, there cannot be any triangle with the given side lengths, thus proving our conjecture.
4x + 5y = 4(2) + 5(1) = 8 + 5 = 13
Answer:
Step-by-step explanation:
Given the equation
4x+12y=72
The equation of a line can written as
y=mx+c
Where m is the slope
And c is the intercept on y axis
Then, we need to write the equation given in the form of equation of a line (y=mx+c), by making y subject of the formula
4x+12y=72
12y=-4x+72
Divide through by 12
y=-4x/12 + 72/12
y=-⅓x+6
Then, comparing with equation of a line shows that
m=-⅓ and c=6
So we need to get another linen that is perpendicular to this line and passes through the point (-9,6)
The slope of the line perpendicular to another line is given as
m1=-1/m2
Then, m1=-1÷-⅓
Then, the slope of the perpendicular line is 3
Then, m=3
So apply this to equation of the line
y=mx+c
Then, y=3x+c
So to know c, we will insert the point given(-9,6), x=-9 and y=6
y=3x+c
6=3(-9)+c
6=-27+c
Then, c=6+27
c=33
Then, the equation of line becomes
y=3x+33
Answer:
.
Step-by-step explanation:
Analysis of variance (ANOVA) "is used to analyze the differences among group means in a sample".
The sum of squares "is the sum of the square of variation, where variation is defined as the spread between each individual value and the grand mean"
If we assume that we have groups (A,B,C) and on each group we have sample of size (6,5,6) respectively , on each group we can define the following formulas of variation:
And we have this property
The degrees of freedom for the numerator on this case is given by where k =3 represent the number of groups.
The degrees of freedom for the denominator on this case is given by .
And the total degrees of freedom would be
On this case the correct answer would be 2 for the numerator and 14 for the denominator.
Best answer
14
D. 192in^2
This would be a simple area problem with a triangle. REMEMBER THIS EQUATION: a=bh*1/2 (b for base and h for height, these are multiplied together then that answer is halved out.)
So we just need to plug in our values into the equation, so the equation would look like a= (16)*(24)*1/2. 16 times 24 would then give you 384, you could either divide by 2 or multiply by 0.5 to get the next answer, as long as your HALVING the answer.
So we have our bh value so now we can multiply by 1/2 which will give us 384*1/2 which leaves us with 192.
I have also attached a photo of doing a longer(ish) way than this, that also proves that this equation works. Either one will provide you an answer.