Answer: 1.414x10^24 molecules in 94.4g MgO
Explanation: molar mass MgO 40.204
molecules in 40.204 g MgO = avogadro number
molecules in 94.4 g MgO = (94.4/40.204)*avogadro number
(94.4/40.204)*6.02214076*10^23 = 14.14x10^23
Opposing reactions are constantly occurring at equal rates
favoring the formation if fewer miles if gaseous products
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Sodium , bromine zinc magnesium sulphur nitrogen potassium oxygen lead
