The equation can still be solved but it should be stated clearly at what value of would the equation be undefined. For instance, you have an expression,
1/x+2
When x is equal to -2, the denominator will be 0 resulting to an undefined solution. The value of x here can be any real number except -2.
8,887 cans divided by 27 classrooms is 329.1481 so each class donated about
329 cans
3=y and 2=x
Pretty sure that’s right
Y = 5x - 2
9y = -2x + 10
9y = 3x + 8
y = (3/9)x + 8/9