Answer:
The object will reach its highest point 0.5 seconds after it has been thrown.
Step-by-step explanation:
The object reaches its maximum height when velocity is equal to zero, the velocity is the derivative of function height. That is:
(1)
Where is the velocity of the object at time , in feet per seconds.
If we know that and , then the time when object reaches its highest point is:
The object will reach its highest point 0.5 seconds after it has been thrown.
Y= 21 so HQE = 42 and AQG= 21
Answer:
-1.123m+0.3
or in fraction form -9/8m+3/10
Step-by-step explanation:
first you subtract 7/8 from 2
then you subtract again 9/10 from 3/5
Answer:
The answer will be D. (2,4)