find 2 positive integers whose difference is 1 and the difference of their squares is 5 pls help i would appreciate it.
1 answer:
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Vertex is (h,k)
se see vertex is (1,-4)
y=a(x-1)^2-4
find a
another point is (4,-2)
-2=a(4-1)^2-4
-2=a(3)^2-4
-2=9a-4
add 4
2=9a
divide b 9
2/9=a
se see vertex is (1,-4)
y=a(x-1)^2-4
find a
another point is (4,-2)
-2=a(4-1)^2-4
-2=a(3)^2-4
-2=9a-4
add 4
2=9a
divide b 9
2/9=a