25.3 is what i got for the first image.
I can figure out this is a frefall motion.
Starting from rest => Vo = 0
Then, use the equation: d = [1/2]gt^2 => t = √(2d/g)
d = width of a black/clear stripe pair = 5cm = 0.05m
g ≈ 10 m/s^2 (the real value is about 9.81 m/s^2)
t =√(2*0.05m/10m/s^2) = 0.1 s
Answer: approximately 0.1 s
Answer:
Sorry if I get it wrong:
Answer: 3,840in
Step-by-step explanation:
PROBLEM ONE
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Solving for x in 2x + 5y > -1.
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Step 1 ) Subtract 5y from both sides.
2x + 5y > -1
2x + 5y - 5y > -1 - 5y
2x > -1 - 5y
Step 2 ) Divide both sides by 2.
2x > -1 - 5y
So, the solution for x in 2x + 5y > -1 is...
•
Solving for y in 2x + 5y > -1.
•
Step 1 ) Subtract 2x from both sides.
2x + 5y > -1
2x - 2x + 5y > -1 - 2x
5y > -1 - 1x
Step 2 ) Divide both sides by 5.
5y > -1 - 1x
So, the solution for y in 2x + 5y > -1 is...
•
PROBLEM TWO
•
Solving for x in 4x - 3 < -3.
•
Step 1 ) Subtract 3 from both sides.
4x - 3 < -3
4x -3 - 3 < -3 - 3
4x < 0
Step 2 ) Divide both sides by x.
4x < 0
x < 0
So, the solution for x in 4x - 3 < -3 is...
x < 0
•
•
- <em>Marlon Nunez</em>
Answer:
c=2.4a+2537.8
a=-2.5/6c+1057.4
Step-by-step explanation:
solve for c:
2.50c+6a=6344.50
-6a -6a
2.50c=-6a+6344.50
/2.50 /2.50 /2.50
c=2.4a+2537.8
solve for a:
2.50c+6a=6344.50
-2.5c -2.5c
6a=-2.5c+6344.50
/6 /6 /6
a=-2.5/6c+1057.4