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2 years ago

What is the ostrich’s average acceleration from 9.0 to 18s

Physics

1 answer:

algol [13]2 years ago

3 0

Answer:

Explanation:

10.00 5

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Which best describes how heat energy moves within a system?

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Heat energy is transferred from warmer objects to cooler objects.

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2 years ago

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What is your displacement if you travel 5 miles north to the store

kumpel [21]

Answer:

5miles North

Explanation:

The displacement to the store is 5miles northward.

Displacement is the distance traveled in a specific direction. Displacement is a vector quantity.

A vector has both magnitude and direction.

The magnitude is the amount of that quantity

The direction is its orientation from a reference.

Therefore, the displacement is 5miles north

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_______ was the first person to propose the idea of moving continents as a scientific hypothesis.

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The answer is b alfred wegener

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Alpha particles, each having a charge of +2e and a mass of 6.64 ×10-27 kg, are accelerated in a uniform 0.50 T magnetic field to

sergij07 [2.7K]

Answer:

$KE=1.2036\times 10^{-12}\ J$

Explanation:

Given:

charge on the alpha particle, $q=2e=3.2\times 10^{-19}\ C$

mass of the alpha particle, $m=6.64\times 10^{-27}\ kg$

strength of a uniform magnetic field, $B=0.5\ T$

radius of the final orbit, $r=0.5\ m$

During the motion of a charge the magnetic force and the centripetal forces are balanced:

$q.v.B=m.\frac{v^2}{r}$

$m.v=q.B.r$

where:

v = velocity of the alpha particle

$v=\frac{q.B.r}{m}$

$v=\frac{3.2\times 10^{-19}\times 0.5\times 0.5}{6.64\times 10^{-27}}$

$v=1.2048\times 10^{7}\ m.s^{-1}$

Here we observe that the velocity of the aprticle is close to the velocity of light. So the kinetic energy will be relativistic.

We firstly find the relativistic mass as:

$m'=\frac{1}{\sqrt{1-\frac{v^2}{c^2} } } \times m$

$m'=\frac{6.64\times 10^{-27}}{\sqrt{1-\frac{(1.2048\times 10^7)^2}{(3\times 10^8)^2} } }$

$m'=6.6533\times10^{-27}\ kg$

now kinetic energy:

$KE=m'.c-m.c$

$KE=6.6533\times 10^{-27}\times (3\times 10^8)^2-6.64\times 10^{-27}\times (3\times 10^8)^2$

$KE=1.2036\times 10^{-12}\ J$

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2 years ago

What is the momentum of a 750kg car traculing at a velocity of 24m/s

m_a_m_a [10]

The answer is 18000 kgm/s

Momentum is mass times velocity so just do 750•24.

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2 years ago