Choose the quadratic equation that has a leading coefficient of 8 and solutions -10 and 7/8

Mathematics

1 answer:

Maru [420]2 years ago

6 0

Answer:

$f(x)=8x^2+73x-70$

Step-by-step explanation:

We are given

zeros as -10 and 7/8

now, we can set up function as

$f(x)=a(x-(-10))(x-\frac{7}{8})$

now, we are given that

leading coefficient is 8

so, a=8

now, we can plug it

$f(x)=8(x-(-10))(x-\frac{7}{8})$

now, we can simplify it

$f(x)=8\left(x^2+\frac{73x}{8}-\frac{35}{4}\right)$

so, we get

$f(x)=8x^2+73x-70$

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Step-by-step explanation:

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