The unknown digit is 7 because 6.471 is greater than 6.470 and less than 6.48.
Solution-
First 9 letters of alphabet are- A,B,C,D,E,F,G,H,I
Total number of ways of selection of 4 letters from 9 alphabets = 9C4
=9!÷((4!).(9-4)!) = 9!÷(4!×5!) = (9×8×7×6)÷(24) = 126
The number of ways of arranging these 4 numbers = 4! = 24
∴ Total number of possible permutations = 9C4×4! = 126×24 = 3024
∴ option number 2 is correct.
The answer I came up with was ×^6-4. Just rewrite it. I hope this was helpful.
Answer:
3
Step-by-step explanation:
mark brainliest
Step-by-step explanation:
- (a+2b+30)-(40+36-5a)
- a+2b+30-40-36+5a
- 6a+2b-46
hope it helps.
