First we need to calculate t(4) because x=4 for 4 shifts.
t(4) = 4*4 +3 = 19
Now because function "c" is declared as c(t(x)) for value x=4 we are searching c(19)! because t(4) = 19
c(19) = 2*19 + 5 = 43.
Answer is 43
(4,-16) factor 3/4
3/4 ×4=3 , -16×3/4= -12
B' (3,-12)
-- The first urn has 9 balls in it all together, and 2 of them are white.
If you don't peek, then the prob of pulling out a white ball is 2/9 .
-- The second urn has 13 balls in it all together, and 3 of them are white.
If you don't peek, then the prob of pulling out a white ball is 3/13 .
-- The probability of being successful BOTH times is
(2/9) x (3/13) = ( 6/117 ) = about 0.0513 or 5.13% (rounded)
Answer:
I think the answer is all of the above