<span>Heat energy is transferred from warmer objects to cooler objects.
</span>
Answer:
73325J
Explanation:
Given parameters:
Mass of water = 0.5kg
Initial temperature = 30°C
Final temperature = 65°C
Specific heat capacity = 4190J/kg°C
Unknown:
Amount of energy absorbed = ?
Solution:
The amount of energy absorbed can be derived using the expression below;
H = m c Δt
H is the amount of energy
m is the mass
c is the specific heat
Δt is the change in temperature
H = 0.5 x 4190 x (65 - 30 )
H = 73325J
Answer:
t = 10.1 s
d = 2020 m
Explanation:
Time to drop from vertical rest
h = ½gt²
t = √(2h/g) = √(2(500)/9.8) = 10.1 s
d = vt = 200(10.1) = 2020 m
Answer:
a = 120 m/s²
Explanation:
We apply Newton's second law in the x direction:
∑Fₓ = m*a Formula (1)
Known data
Where:
∑Fₓ: Algebraic sum of forces in the x direction
F: Force in Newtons (N)
m: mass (kg)
a: acceleration of the block (m/s²)
F = 1200N
m = 10 kg
Problem development
We replace the known data in formula (1)
1200 = 10*a
a = 1200/10
a = 120 m/s²
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I hope this helps, have a great day! :)