Answer:
$896
Step-by-step explanation:
We are given that
Charge of 1 yard for each custom-made banner=$28
Length of 1 piece=15 yards
Length of another piece=2 yards
We have to find that how much money payed by Ms.Gill for all three banners.
According to question
Cost of 15 yards long banner=$420
Cost of 2 piece of 15 yards long banner==$840
Cost of 2 yards long banner==$56
Total cost of 3 piece of banners=840+56=$896
Hence, Ms gill pay for all three banners=$896
Your Welcome;)
The value of
Step-by-step explanation:
Given: The function
Using this formula, we need to find the value of
Hence, we need to substitute by to find the value of
Multiplying the term by , we get,
Adding the constant term,
Thus, the value of is
To find the interquartile range, you will list the data that is presented in the stem and leaf plot.
Find the median of the data (30.5)
Find the median of the lower half and the median of the upper half.
Subtract these two values.
The data are <u>20</u>, 25, 30, 30, 31, 40, 41, <u>49</u>.
27.5 40.5
40.5-27.5 = 13
The interquartile range is 13.
Answer:
Question 18
=$3.33
Step-by-step explanation:
i)
26/100 x 4.5
=1.17
(the discount price)
ii)
$4.5-$1.17
=$3.33
Amount financed
320−100=220
Total paid
100+25×12=400
Interest paid
400−320=80
Interest rate=(2yc)÷(m (n+1))
I=(2×12×80)÷(220 (12+1))
I=(2×12×80)÷(220×13)
I=0.67×100
I=67%