Answer:
Molarity of NaOH solution is 1.009 M
Explanation:
Molar mass of HCl is 36.46 g/mol
Number moles = (mass)/(molar mass)
So, 0.8115 g of HCl = HCl = 0.02226 moles HCl
1 mol of NaOH neutralizes 1 mol of HCl.
So, if molarity of NaOH solution is S(M) then moles of NaOH required to reach endpoint is
So,
or, S = 1.009
So, molarity of NaOH solution is 1.009 M
Answer:
The volumetric ratio is 0,71
Explanation:
Let's begin with the equation:
(1)
Where:
Db: Blend Density, Mb: Blend Mass and Vb: Blend Volume
And we know: (2)
Where:
Vg: Gasoline Volume and Vk: Kerosene Volume
Therefore replacing (2) into (1):
(3)
Where:
Dg: Gasoline Density and Dk: Kerosene Density
The specific gravity is defined as:
Therefore:
Where:
Dref: Reference Density
SGb: Blend Specific Gravity
SGg: Gasoline Specific Gravity (which is 0.7 approximately)
SGk: Kerosene Specific Gravity
Replacing these equations into (3) we get:
Replacing with the Specific Gravity data, we obtain:
Answer: D. 19.9 g hydrogen remains.
Explanation:
To calculate the moles, we use the equation:
a) moles of
b) moles of
According to stoichiometry :
1 mole of require 1 mole of
Thus 0.0787 moles of require= of
Thus is the limiting reagent as it limits the formation of product and acts as the excess reagent. (10.0-0.0787)= 9.92 moles of are left unreacted.
Mass of
Thus 19.9 g of remains unreacted.
Answer:
calcium chloride deihydrate