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2 years ago

Write a balanced equation for the combustion of liquid ethanol in air.

Chemistry

1 answer:

Katyanochek1 [597]2 years ago

7 0

Answer: The balanced chemical equation for the combustion of liquid ethanol is written below.

Explanation:

Combustion reactions are defined as the reactions in which a hydrocarbon reacts with oxygen gas to produce carbon dioxide and water. Heat is released during these reactions.

A balanced chemical equation is defined as the equation in which total number of individual atoms on the reactant side is equal to the total number of individual atoms on product side.

The balanced chemical equation for the combustion of liquid ethanol follows:

$C_2H_5OH(l)+3O_2(g)\rightarrow 2CO_2(g)+3H_2O(g)$

By Stoichiometry of the reaction:

1 mole of liquid ethanol reacts with 3 moles of oxygen gas to produce 2 moles of carbon dioxide gas and 3 moles of water vapor.

Hence, the balanced chemical equation for the combustion of liquid ethanol is written above.

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What's the oxidation number of Li in LiNO3

Studentka2010 [4]

Explanation:

To solve this problem, we need to set up an algebraic equation. Let us first understand the meaning of oxidation number.

The oxidation number is the formal charge assigned to an atom present in a molecule or formula unit

The algebraic sum of all oxidation numbers of atoms in an ion containing more than one kind of atom is the charge on the ion.

The algebraic sum of all oxidation number of atoms in a neutral compound is zero;

The radical NO₃ has a formal charge of -1;

let the oxidation number of Li = x

x + (-1) = 0

x = + 1

learn more:

Oxidation number brainly.com/question/10017129

#learnwithBrainly

4 0

2 years ago

Consider a balloon with volume V. It contains n moles of gas and has an internal pressure of P. The temperature of the gas is T.

Maksim231197 [3]

Answer:

V₂ = 0.6 V.

Explanation:

We can use the general law of ideal gas: PV = nRT.

where, P is the pressure of the gas in atm.

V is the volume of the gas in L.

n is the no. of moles of the gas in mol.

R is the general gas constant,

T is the temperature of the gas in K.

If n is constant, and have different values of P, V and T:

(P₁V₁T₂) = (P₂V₂T₁).

V₁ = V, P₁ = P, T₁ = T.

V₂ = ??? V, P₂ = 1.25 P, T₂ = 0.75 T.

∴ V₂ = (P₁V₁T₂)/(P₂T₁) = (P)(V)(0.75 T)/(1.25 P)(T) = 0.6 V.

3 0

2 years ago

Read 2 more answers

The volume of a gas is 550 mL at 960 mm Hg and 200.0 C. What volume

Masja [62]

Answer:

The volume will be 568.89 mL.

Explanation:

Boyle's law says that "The volume occupied by a given gaseous mass at constant temperature is inversely proportional to pressure"

Boyle's law is expressed mathematically as:

Pressure * Volume = constant

or P * V = k

Gay-Lussac's law indicates that when there is a constant volume, as the temperature increases, the pressure of the gas increases. And when the temperature is decreased, the pressure of the gas decreases. That is, the pressure of the gas is directly proportional to its temperature. Gay-Lussac's law can be expressed mathematically as follows:

$\frac{P}{T}=k$

Where P = pressure, T = temperature, K = Constant

Finally, Charles's law indicates that as the temperature increases, the volume of the gas increases and as the temperature decreases, the volume of the gas decreases. In summary, Charles's law is a law that says that when the amount of gas and pressure are kept constant, the quotient that exists between the volume and the temperature will always have the same value:

$\frac{V}{T}=k$

Combined law equation is the combination of three gas laws called Boyle's, Charlie's and Gay-Lusac's law:

$\frac{P*V}{T} =k$

Studying an initial state 1 and a final state 2, it is fulfilled:

$\frac{P1*V1}{T1} =\frac{P2*V2}{T2}$

In this case:

P1= 960 mmHg
V1= 550 mL
T1= 200 C= 473 K (being 0 C=273 K)
P2= 830 mmHg
V2= ?
T2= 150 C= 423 K

Replacing:

$\frac{960 mmHg*550 mL}{473K} =\frac{830 mmHg*V2}{423 K}$

Solving:

$V2=\frac{423 K}{830 mmHg} *\frac{960 mmHg*550 mL}{473K}$

V2= 568.9 mL

The volume will be 568.89 mL.

4 0

2 years ago

What is the standard potential, e∘celle∘cell, for this galvanic cell? use the given standard reduction potentials in your calcul

Olin [163]

The standard potential for the given galvanic cell is 0.477 V

<h3>What is electrode potential?</h3>

The electrode potential is the electromotive force of a galvanic cell built using a standard reference electrode and another electrode whose potential is to be found.

There are two types of electrode potential

Oxidation potential - The potential associated with oxidation reaction is known as oxidation potential

Reduction potential - The potential associated with reduction reaction is known as reduction potential

At the anode, oxidation occurs

$Sn(s)\rightarrow Sn^{2+}(aq)+2e^-$

At the cathode, reduction occurs

$Cu^{2+}(aq)+2e^-\rightarrow Cu(s)$

$E^o_{cell} =E^o_{cathode} -E^o_{anode}$

= 0.337 - (-0.140)

= 0.477 V

Thus, The standard potential for the given galvanic cell is 0.477 V

Learn more about electrode potential:

brainly.com/question/17362810

#SPJ4

Disclaimer: The question was given incomplete on the portal. Here is the complete question

Question: What is the standard potential, E∘cell, for this galvanic cell? Use the given standard reduction potentials in your calculation as appropriate.

$Sn^{2+}(aq)+2e^-\rightarrow Sn(s)$ , E°red=−0.140 V