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2 years ago

HELP!! URGENT!! DUE TODAY

Mathematics

2 answers:

krok68 [10]2 years ago

5 0

Answer:

I think its 20 to 60 or something like that....

Step-by-step explanation:

grigory [225]2 years ago

3 0

Answer:ITS 8

Step-by-step explanation:

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It takes Adara 3 hours to drive from Ashdown to Bridgeton at an average speed of 60 mph.

Scrat [10]

Answer:

61.2 mph

Step-by-step explanation:

Let's first calculate the individual legs of Adara's trip in terms of both time and distance:

Ashdown to Bridgeton

3 hr at 60 mph = 180 miles in 3 hours

Bridgeton to Carton

30 miles at 70 mph: 30 miles/(70 miles/hour) = 0.429 hours

Total Trip

Miles = 180 + 30 = 210 miles

Time = 3 + 0.429 = 3.429 hours

Average speed is (210 miles)/(3.429 hours) = 61.25 or 61.2 miles/hour to 1 decimal point.

8 0

2 years ago

Which expression is equivalent to 3x + 5 y + y - 2y

LuckyWell [14K]

Answer:

Step-by-step explanation:

3x+5y+y-2y = 3x +y(5+1-2)

= 3x +4y

6 0

2 years ago

Evaluate each using the values given. zy^2; use y = 2, and z = 4

Natali5045456 [20]

4(2)^2
4(4)=16
I would assume it’s this

7 0

2 years ago

Perform the indicated operation. <img src="https://tex.z-dn.net/?f=x%20%2B%205%20%2F%203" id="TexFormula1" title="x + 5 / 3"

Salsk061 [2.6K]

Answer:

$x + \frac{5}{3}-x - \frac{3}{2} = \frac{1}{6}$

Step-by-step explanation:

Given

$x + \frac{5}{3}-x - \frac{3}{2}$

Required

Solve

$x + \frac{5}{3}-x - \frac{3}{2}$

Collect like terms

$x + \frac{5}{3}-x - \frac{3}{2} = x -x+ \frac{5}{3} - \frac{3}{2}$

$x + \frac{5}{3}-x - \frac{3}{2} = \frac{5}{3} - \frac{3}{2}$

Take LCM

$x + \frac{5}{3}-x - \frac{3}{2} = \frac{10 -9}{6}$

$x + \frac{5}{3}-x - \frac{3}{2} = \frac{1}{6}$

5 0

2 years ago

Chemists use pH as a measure of acidity or alkalinity of a solution. It uses the concentration of hydrogen ions H+ in a logarith

SpyIntel [72]

Answer:

$g(f(d)) = -dlog_{10}(0.5 * 10^{-4})$

Step-by-step explanation:

Given

$f(d) = (0.5 * 10^{-4})^d$

$g(H+) = -log_{10}(H+)$

Required

Find the composite function g(f(d))

We have:

$g(H+) = -log_{10}(H+)$

Substitute f(d) for H+

$g(f(d)) = -log_{10}(f(d))$

Substitute $f(d) = (0.5 * 10^{-4})^d$

$g(f(d)) = -log_{10}((0.5 * 10^{-4})^d)$

Apply law of logarithm

$g(f(d)) = -dlog_{10}(0.5 * 10^{-4})$

Hence, the function is:

$g(f(d)) = -dlog_{10}(0.5 * 10^{-4})$

7 0

2 years ago

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