Answer:
128√5/3 mm³
Step-by-step explanation:
Since we are not told what to find, we can as well look for the volume of the pyramid
Volume of a square pyramid: V = (1/3)a²h
a is the side length of the square
h is the height of the pyramid
Given
a = 8mm
l² = (a/2)² + h²
l² = (a/2)² + h²
6² = (8/2)² + h²
h² = 6² - 4²
h² = 36 - 16
h² = 20
h = √20
Volume of a square pyramid = (1/3)*8²*√20
Volume of a square pyramid = 1/3 * 64 * 2√5
Volume of a square pyramid = 128√5/3 mm³
Answer:
25/9
Step-by-step explanation:
25/9
The answer is (1/2)xe^(2x) - (1/4)e^(2x) + C
Solution:
Since our given integrand is the product of the functions x and e^(2x), we can use the formula for integration by parts by choosing
u = x
dv/dx = e^(2x)
By differentiating u, we get
du/dx= 1
By integrating dv/dx= e^(2x), we have
v =∫e^(2x) dx = (1/2)e^(2x)
Then we substitute these values to the integration by parts formula:
∫ u(dv/dx) dx = uv −∫ v(du/dx) dx
∫ x e^(2x) dx = (x) (1/2)e^(2x) - ∫ ((1/2) e^(2x)) (1) dx
= (1/2)xe^(2x) - (1/2)∫[e^(2x)] dx
= (1/2)xe^(2x) - (1/2) (1/2)e^(2x) + C
where c is the constant of integration.
Therefore,
∫ x e^(2x) dx = (1/2)xe^(2x) - (1/4)e^(2x) + C
First we must apply the Quotient rule that states,
This means that our derivative becomes,
Now we need to calculate 
and 
From here the new equation looks like,
And that is the final result.
Hope this helps.
r3t40
Answer:
b is right
Step-by-step explanation:
