Hello
<span>D. 2 imaginary roots (complex conjugates)</span>
Answer:
96
Step-by-step explanation:
Using side b as the base, 4 points makes 3 bases (the space in between). With three bases, you can have 3 bases of 1 segment, 2 bases of 2 segments, and 1 base of 3 segments. This equals 6 bases. Each of these can connect to a point on line a. 6x6=36
Using side a as the base, 6 points makes 5 bases. With 5 bases, you can have 5 bases of 1 segment, 4 bases of 2 segments, 3 bases of 3 segments, 2 bases of 4 segments, and 1 base of 5 segments. This equals 15 bases. Each of these can connect to a point on line b. 15x4=60
36+60=96
I’m sorry, I wish I knew this one and I would help
Answer:
9
Step-by-step explanation:
Using the property that
a
m
a
n
=
a
m
−
n
, we have
3
4
2
2
=
3
4
−
2
=
3
2
=
9
Note that if we evaluated the numerator and denominator first, we would arrive at the same result:
3
4
3
2
=
81
9
=
9
