Answer:
1) 0.1667
2) 0.8333
3) 1
Step-by-step explanation:
Let A be the event that 3 is observed on the first trial.
Let B be the event that at least two trials are required to observe a 3
a) A six-sided die has 6 possible outcomes of 1,2,3,4,5,6
3 is one of the six possible outcomes
P(A) = no of favourable outcomes /no of possible outcomes
P(A) = 1/6 = 0.1667
b) The event of requiring at least two trials to observe a 3 is the event of not observing a 3 on the first trial.
P(B) = P(A')
P(A')= 1 - P(A)
P(B) = 1 - 1/6
= 5/6 = 0.8333
c) P(AnB) = P(A) + P(B)
= 1/6 + 5/6
= 6/6 = 1
I think there's an error with this question. Mind to check it back and tell me the detail?
Answer:
Gross pay for each day is 5h + 8 dollars.
Step-by-step explanation:
Given:
Number of days = 7
Gross pay for 7 day = 35h+56 dollars.
We need to find the gross pay for each day
Also given Harriet earns the same amount of money each day.
Hence
For 7 days = 35h + 56 dollars
for 1 day = gross pay for each day.
By using Unitary method we get;
Gross pay for each day =
Hence gross pay for each day is 5h + 8.