For y = 4x + 2x2-x3, show how to find the value for y, when x = 2. show work
1 answer:
Y(x)=4x+2x^2-x^3, when x=2
y(2)=4(2)+2(2^2)-(2^3)
y(2)=8+2(2*2)-(2*2*2)
y(2)=8+2(4)-8
y(2)=8+8-8
y(2)=8
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<h2>Hope it helps you.</h2>
