Answer: (0,3)
Step-by-step explanation:
You follow the formulas to find the x and y of the dividing points.
Xp= x1+ a/a+b (x2-x1)
Xp= 10+5/5+3(-6-10)
Xp=10+5/8(-16)
Solve the problem above and you end up with “0” as your x.
Yp= y1+ a/a+b (y2-y1)
Yp= -2+ 5/8 (6+2)
Yp= -2+ 5/8 (8)
Solve this problem above and you end up with “3” as your y. Therefore, the point that divides the line segment between (10, -2) and (-6,6) into a ratio of 5:3 is (0, 3).
<span>The difference between two integers is at most 16
x1 - big integer
x2- small integer
</span><span>the smaller integer is 12
so
x2 = 12
substitution
</span>
<span>
solve for x1
however, note the fact larger
thus meaning
x1 > x2 applies to this problem
</span>
Answer:
(p ∧ q)’ ≡ p’ ∨ q’
Step-by-step explanation:
First, p and q have just four (4) possibilities, p∧q is true (t) when p and q are both t.
p ∧ q
t t t
t f f
f f t
f f f
next step is getting the opposite
(p∧q)'
<em>f</em>
<em> t</em>
<em> t</em>
<em> t</em>
Then we get p' V q', V is true (t) when the first or the second is true.
p' V q'
f <em>f</em> f
f <em>t</em> t
t <em>t</em> f
t <em>t</em> t
Let's compare them, ≡ is true if the first is equal to the second one.
(p∧q)' ≡ (p' V q')
<em>f f </em>
<em> t t</em>
<em> t t</em>
<em> t t</em>
Both are true, so
(p ∧ q)’ ≡ p’ ∨ q’
In order to utilize the graph, first you have to distinguish which graph accurately pertains to the two functions.
This can be done by rewriting the equations in the form y = mx + b which can be graphed with ease; where m is the slope and b is the y intercept.
-x^2 + y = 1
y = x^2 + 1
So this will be a basic y = x^2 parabola where the center intercepts on the y axis at (0, 1)
-x + y = 2
y = x +2
So this will be a basic y = x linear where the y intercept is on the y axis at (0, 2)
The choice which depicts these two graphs correctly is the first choice. The method to find the solutions to the system of equations by using the graph is by determining the x coordinate of the points where the two graphed equations intersect.