The difference is intensity is assessed using a special scale and magnitude is measure of the size ( for example a earthquake)
Answer: 6m/s
Explanation:
Using the law of conservation of momentum, the change in momentum of the bodies before collision is equal to the change in momentum after collision.
After collision, the two objects will move at the same velocity (v).
Let mA and mB be the mass of the two objects
uA and uB be their velocities before collision.
v be their velocity after collision
Since the two objects has the same mass, mA= mB= m
Also since object A is at rest, its velocity = 0m/s
Velocity of object B = 12m/s
Mathematically,
mAuA + mBuB = (mA+mB )v
m(0) + m(12) = (m+m)v
0+12m = (2m)v
12m = 2mv
12 = 2v
v = 6m/s
Therefore the speed of the composite body (A B) after the collision is 6m/s
Answer:0.0909 kJ/K
Explanation:
Given
Temperature of hot Reservoir
Temperature of cold Reservoir
Heat of 100 kJ is transferred form hot reservoir to cold reservoir
Hot Reservoir is Rejecting heat therefore
Heat is added to Reservoir therefore
Entropy change for system
As entropy change is Positive therefore entropy Principle is satisfied
The possible units for impulse would be:
<span>(N. s)
</span><span>(kg. m/s)</span>