Answer:
The final pressure in the container at 0°C is 2.49 atm
Explanation:
We apply the Ideal Gases law to know the global pressure.
We need to know, the moles of each:
P He . V He = moles of He . R . 273K
(1atm . 4L) / R . 273K = moles of He → 0.178 moles
P N₂ . V N₂ = moles of N₂ . R . 273K
(1atm . 6L) / R . 273K = moles of N₂ → 0.268 moles
P Ar . V Ar = moles of Ar . R . 273K
(1atm . 10L) / R . 273K = moles of Ar → 0.446 moles
Total moles: 0.892 moles
P . 8L = 0.892 mol . R . 273K
P = ( 0.892 . R . 273K) / 8L = 2.49 atm
R = 0.082 L.atm/mol.K