Step two shows the step where he applied the distributive property.
This is because he distributed the terms in the first bracket with the terms in the second bracket
Answer:
To answer items such as this, we directly substitute the a + 2 to the all the x's in the function such that,
f(a + 2) = (3 + a + 2) / (a + 2 - 3)
Simplifying the function generated above,
f(a + 2) = (5 + a) / (a - 1)
Answer:
Interquartile range
Step-by-step explanation:
Range = 32, 29
Median = -6, 3
Upper quatile = 2, 13
Interquartile range = 11, 23
==> Interquartile range has the greatest difference of 23-11 = 12
Strange question, as normally we would not calculate the "area of the tire." A tire has a cross-sectional area, true, but we don't know the outside radius of the tire when it's mounted on the wheel.
We could certainly calculate the area of a circle with radius 8 inches; it's
A = πr^2, or (here) A = π (8 in)^2 = 64π in^2.
The circumference of the wheel (of radius 8 in) is C = 2π*r, or 16π in.
The numerical difference between 64π and 16π is 48π; this makes no sense because we cannot compare area (in^2) to length (in).
If possible, discuss this situatio with your teacher.