Answer: 361° C
Explanation:
Given
Initial pressure of the gas, P1 = 294 kPa
Final pressure of the gas, P2 = 500 kPa
Initial temperature of the gas, T1 = 100° C = 100 + 273 K = 373 K
Final temperature of the gas, T2 = ?
Let us assume that the gas is an ideal gas, then we use the equation below to solve
T2/T1 = P2/P1
T2 = T1 * (P2/P1)
T2 = (100 + 273) * (500 / 294)
T2 = 373 * (500 / 294)
T2 = 373 * 1.7
T2 = 634 K
T2 = 634 K - 273 K = 361° C
It really depends on how far or close the planet is from the sun
Answer:
1) Newton's first law of motion states an object will remain at rest or in uniform will be in uniform motion in a straight line unless a force acts on it
2) Newton's second law states the acceleration of an object is directly proportional to the applied force acting on an object and inversely proportional to the mass of the object
Explanation:
1) With Newton's first law, we are able arrange things within a space and schedule meetings in time knowing that they will remain in place unless an external force changes their positions
2) An example of Newton's second law of motion is that small objects such as a ball are easily accelerated and can be given appreciable acceleration for flight by single, one time contact (such as kicking the ball) while larger objects such as a rock require sustained force application to change their location.
P (gravitational force) = m (mass) x g
<=> P = 0.05 x 10
<=> P = 0.5N
Answer:
The final angular speed is 16.1 rad/s
Explanation:
Given;
initial moment of inertia, I₁ = 2.56 kg.m²
final moment of inertia, I₂ = 0.40 kg.m²
initial angular speed, ω₁ = 0.4 rev/s = 2.514 rad/s
Apply the principle of conservation of angular momentum;
I₁ω₁ = I₂ω₂
where;
ω₂ is the final angular speed
ω₂ = (I₁ω₁) / (I₂)
ω₂ = (2.56 x 2.514) / (0.4)
ω₂ = 16.1 rad/s
Therefore, the final angular speed is 16.1 rad/s