Answer : The initial rate of the reaction is, 
Explanation :
First we have to calculate the rate constant of the reaction.
Expression for rate law for first order kinetics is given by :
![k=\frac{2.303}{t}\log\frac{[A_o]}{[A]}](https://tex.z-dn.net/?f=k%3D%5Cfrac%7B2.303%7D%7Bt%7D%5Clog%5Cfrac%7B%5BA_o%5D%7D%7B%5BA%5D%7D)
where,
k = rate constant = ?
t = time taken for the process = 44 s
![[A_o]](https://tex.z-dn.net/?f=%5BA_o%5D)
= initial amount or concentration of the reactant = 0.1108 M
![[A]](https://tex.z-dn.net/?f=%5BA%5D)
= amount or concentration left time 44 s = 0.0554 M
Now put all the given values in above equation, we get:
Now we have to calculate the initial rate of the reaction.
Initial rate = K [A]
At t = 0, ![[A]=[A_o]](https://tex.z-dn.net/?f=%5BA%5D%3D%5BA_o%5D)
Initial rate = 0.0157 × 0.1108 =
Therefore, the initial rate of the reaction is,
Answer: 29.0 years
Explanation:
Expression for rate law for first order kinetics is given by:
where,
k = rate constant
t = age of sample
a = let initial amount of the reactant
a - x = amount left after decay process
a) for completion of half life:
Half life is the amount of time taken by a radioactive material to decay to half of its original value.
b) for decomposition of 80 % of reactant
The age of a suspected vintage wine that is 20 % as radioactive as a freshlybottled specimen is 29.0 years
Answer:
Explanation:
2 NH₄ClO₄ ⇒ N₂ + Cl₂ + 2O₂ + 4 H₂O
2 moles 1 mole
We are required to produce 1.4 moles of N₂ from ammonium perchlorate .
1 mole of N₂ is produced by 2 moles of ammonium perchlorate
1.4 moles of N₂ will be produced by 2 x 1.4 = 2.8 moles of ammonium perchlorate .
Answer is 2.8 moles .
An organism is the level of organization in living things
