Answer:
-4 and 4
Step-by-step explanation:
You count between the zeros as when you jump on a number line or just don't count the zero
-4, -3, -2 ,-1, 0, 1, 2 ,3, 4
Hope this helps
Answer:
35/16 sec ( 2 3/16 sec)
Step-by-step explanation:
This assumes you glove is at height = 0
0 = -16t^2 + 35t
0 = t ( -16t + 35) shows t = 0 ( before you throw it) and t = 35/16 sec
A) domain: [ -5 5 ] range: [ -10 -2 ]
b) y intercept: -2 x intercept: -2 2
c) y= -2
d) x= -2 x= 2
e) None
Answer:
see below
Step-by-step explanation:
Since RT bisects QRS
1/2 QRS = TRS
1/2 ( 9x+214) = -9x+53
Multiply each side by 2
9x +214 = -18x+ 106
Add 18x from each side
9x +214+18x = 106
27x +214 = 106
Subtract 214 from each side
27x = 106-214
27x =-108
Divide by 27
27x/27 = -108/27
x = -4
TRS = -9x+53
=-9 *-4 +53
= 36+ 53
=89
Answer:
A.The mean would increase.
Step-by-step explanation:
Outliers are numerical values in a data set that are very different from the other values. These values are either too large or too small compared to the others.
Presence of outliers effect the measures of central tendency.
The measures of central tendency are mean, median and mode.
The mean of a data set is a a single numerical value that describes the data set. The median is a numerical values that is the mid-value of the data set. The mode of a data set is the value with the highest frequency.
Effect of outliers on mean, median and mode:
- Mean: If the outlier is a very large value then the mean of the data increases and if it is a small value then the mean decreases.
- Median: The presence of outliers in a data set has a very mild effect on the median of the data.
- Mode: The presence of outliers does not have any effect on the mode.
The mean of the test scores without the outlier is:
*Here <em>n</em> is the number of observations.
So, with the outlier the mean is 86 and without the outlier the mean is 86.9333.
The mean increased.
Since the median cannot be computed without the actual data, no conclusion can be drawn about the median.
Conclusion:
After removing the outlier value of 72 the mean of the test scores increased from 86 to 86.9333.
Thus, the the truer statement will be that when the outlier is removed the mean of the data set increases.