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2 years ago

Write the atomic symbols for isotopes with the following characteristics?

1 answer:

7 0

<span>The isotopes are represented with two numbers before the atom symbol. One number means the atomic number (number of protons) and is placed on the left lower corner, the other number is that mass number (number of protons and neutrons) and is placed on the right upper corner. With that, 1) (8, 18) O: 8 is the atomic number and 18 is the mass number; 2) (10, 22) Ne: 10 is the atomic number and 22 is the mass number; 3) (25, 53) Mn: 25 is the atomic number and 53 is the mas number; 4) (11, 24) Na: 11 is the atomic number and 24 is the mass number; (22, 47) Ti: 22 is the atomic number and 47 is the mass number. The two numbers are placed without parentheses, again atomic number on the left lower corner and the mass number on the left upper corner.</span>

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4. A scientific theory is

Airida [17]

Answer:

Option 1

Explanation:

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2 years ago

The total mass of the atmosphere is about 5.00 x 1018 kg. How many moles each of air, O2, and CO2 are present in the atmosphere?

n200080 [17]

<u>Answer:</u> The moles of oxygen and carbon dioxide in air is $3.63\times 10^{19}mol$ and $7.18\times 10^{16}mol$ respectively

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Given mass of atmosphere = $5.00\times 10^{18}kg=5.00\times 10^{21}g$

Average molar mass of atmosphere = 28.96 g/mol

Putting values in above equation, we get:

$\text{Moles of atmosphere}=\frac{5.00\times 10^{21}g}{28.96g/mol}=1.73\times 10^{20}mol$

We know that:

Percent of oxygen in air = 21 %

Percent of carbon dioxide in air = 0.0415 %

Moles of oxygen in air = $\frac{21}{100}\times 1.73\times 10^{20}=3.63\times 10^{19}mol$

Moles of carbon dioxide in air = $\frac{0.0415}{100}\times 1.73\times 10^{20}=7.18\times 10^{16}mol$

Hence, the moles of oxygen and carbon dioxide in air is $3.63\times 10^{19}mol$ and $7.18\times 10^{16}mol$ respectively

6 0

2 years ago

What is the molarity of a solution prepared by dissolving 10.7 g NaI in 0.250 L?0.0714

hjlf

Answer:0.286M

Explanation:

10.7g / 149.89g/mol×0.25L

4 0

2 years ago

Read 2 more answers

What gas law states that pressure and temperature are directly proportional at

Rus_ich [418]

Charles Law is the law that states pressure and temperature are directly proportional at constant volume and miles

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2 years ago

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) Calculating Heat from Thermochemical Equations

SIZIF [17.4K]

A combustion reaction is a reaction that reacts in the presence of oxygen molecules. Methane will release -3115 kJ/mol of heat.

<h3>What is a combustion reaction?</h3>

A combustion reaction includes the reaction between the chemical reactant and oxygen molecule to produce the product. The combustion reaction between methane and oxygen is given as:

CH₄(g) + 2O₂ (g) → CO₂(g) + 2H₂O (l), ΔH = -890 kJ/mol

The stoichiometry coefficient from the reaction gives 1 mole of methane releases -890 kJ/mol enthalpy.

So, 3.5 moles methane will release = 3.5 × -890 = -3115 kJ/mol

Therefore, -3115 kJ/mol of heat is released.

Learn more about combustion reaction here:

brainly.com/question/27823881

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1 year ago