Answer:
-5/2+-1/2√37≤x≤-5/2+1/2√37
Step-by-step explanation:
Step 1: Find the critical points
-x^2-5x+3=0
For this equation: a=-1, b=-5, c=3
−1x^2+−5x+3=0
x=−b±√b2−4ac/2a
x=−(−5)±√(−5)2−4(−1)(3)/2(-1)
x=5±√37
/−2
x=-5/2+1/2√37
Step 2: Check intervals in between critical points
x≤-5/2+1/2 √37 (Doesn't work in original inequality)
-5/2+-1/2√37≤x≤-5/2+1/2√37 (Works in original inequality)
x≥-5/2+1/2 √37 (Doesn't work in original inequality)
Answer:
(0, -2)
Step-by-step explanation:
The y-intercept is where the graph crosses the y-axis when x = 0. As shown in the graph, when x = 0, y = -2, so your answer is (0, -2).
Rule needed: i^2 = -1
Standard form a + bi
(3 + 2i)(7 - 5i) FOIL
3 * 7 = 21
3 * - 5i = - 15i
2i * 7 = 14i
2i * -5i = - 10i^2 = - 10 * -1 = 10
Putting it all back together.
31 - i
SA=201.7cm^2
I used the equation
SA=pi^1/3(6*V)^2/3 in case you have any more questions like this
