Answer:
85.5 km/h
Explanation:
= time interval for first phase = 14 min = h = 0.233 h
= time interval for second phase = 46 min = h = 0.767 h
= average speed for the entire trip = 74 km/h
= average speed in first phase = 36 km/h
= average speed in second phase
= distance traveled in first phase
= distance traveled in first phase
average speed is given as
km/h
Fc=mv^2/r so we get
2000kg*(25m/s)^2/(80m)= 15625N of force
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Answer:
500000000 lbft/s
Explanation:
F = Force or weight = 1000000 lbf
s = Displacement = 10000 ft
t = Time taken = 20 seconds
Work done is given by
Power is given by
One Saucer power is 500000000 lbft/s
As per the question, the velocity of the airplane [v] = 660 miles per hour.
The total time taken by airplane [t] = 3.5 hours.
We are asked to determine the total distance travelled by the airplane during that period.
The distance covered [ S] by a body is the product of velocity with the time.
Mathematically distance covered = velocity × total time
S = v × t
= 660 miles/hour ×3.5 hours
= 2310 miles.
Hence, the total distance travelled by the airplane in 3.5 hour is 2310 miles.