Answer:
an inducer
Explanation:
An Enzyme is a protein molecule found in cells which work as biological catalysts.
They speed up chemical reactions in the body, but do not get used up in the process, and can be used over and over again.
In chemistry inducers are molecules that regulates gene expression, and can bind to protein repressors or activators.
Lactose here acts as an inducer because it inactivates the repressor of an operon.
Answer:
- <u>Higher acidity (lower pH) making it a better cleaning solution because it will be able to kill more microorganisms</u>
Explanation:
The higher the percentage of the vinegar solution, the higher the molar concentration of hydrodium ions, [H₃O⁺].
pH is a measure of the concentration of H₃O⁺ ions:
![pH=\log\dfrac{1}{[H_3O^+]}](https://tex.z-dn.net/?f=pH%3D%5Clog%5Cdfrac%7B1%7D%7B%5BH_3O%5E%2B%5D%7D)
The lower the pH the more acidic the solution.
Thus, the higher the percentage of vinegar, the higher [H₃O⁺], the lower the pH, and the more acidic the solution.
The feature that makes vinegar a good cleaning agent is its acidity: high acidity environments are inhospitable for many microorganisms.
Thus, the advantage of a vinegar with 6 - 15% acetic acid is its higher acidity (lower pH), which makes it more suitable to kill more microorganisms.
Normally during the daylight hours
Answer:
see explanation below
Explanation:
You miss the part of the temperature and pressure. According to what I found this is held under 30 °C (or 303 K) and 1 atm.
The problem states that we can treat this gas as an ideal gas, therefore, we can use the equation of an ideal gas which is:
PV = nRT (1)
Now, the density (d) is calculated as:
d = m/V (2)
We can rewrite (2) in function of mass of volume so:
m = d*V (3)
Now, the moles (n) of (1) can be calculated like this:
n = m /MM (4)
If we replace it in (1) and then, (3) into this we have the following:
PV = mRT/MM ----> replacing (3):
PV = dVRT/MM ----> V cancels out so finallly:
P = dRT/MM
d = P * MM / RT (5)
The molar mass of N2O is 44 g/mol So, replacing all the data we have:
d = 1 * 44 / 0.082 * 303
d = 1.77 g/L
For the reaction 2 K + F2 --> 2 KF,
consider K atomic wt. = 39
23.5 g of K = 0.603 moles, hence following the molar ratio of the balanced equation, 0.603 moles of potassium will use 0.3015 moles of F2. (number of moles, n = 0.3015)
Now, following the ideal gas equation, PV = nRT
P = 0.98 atm
V = unknown
n = 0.3015 moles
R = 82.057 cm^3 atm K^-1mole^-1 (unit of R chosen to match the units of other parameters; see the reference below)
T = 298 K
Solving for V,
V = (nRT)/P = (0.3015 mol * 82.057 cm^3 atm K^-1 mol^-1 * 298 K)/(0.98 atm)
solve it to get 7517.6 cm^3 as the volume of F2 = 7.5176 liters of F2 gas is needed.
2. Use the formula: volume1 * concentration 1 = volume 2 * concentration 2
where, volume 1 and concentration 1 are for solution 1 and volume 2 and solution 2 for solution 2.
Solution 1 = 12.3 M NaOH solution
Solution 2 = 1.2 M NaOH solution
<span>
Solving for volume 1, volume 1 = (12.4 L * 1.2 M)/12.3 M = 0.1366 L </span>
