2 years ago

A triangle has sides measuring 8 inches, 5 inches and 4 inches. How would you classify it?

Mathematics

2 answers:

Zina [86]2 years ago

8 0

Answer:

I wouldn't classify it i would ignore it.

Step-by-step explanation:

statuscvo [17]2 years ago

8 0

Answer:

Acute triangle because the angles are smaller than a right triangle

Step-by-step explanation:

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Write 12/root2 + root18 in the form broot2 where b is an interger

katrin2010 [14]

$\dfrac{12}{\sqrt 2} + \sqrt{18}\\\\\\=\dfrac{12 + \sqrt{18 \times 2}}{\sqrt 2}\\\\\\=\dfrac{12+\sqrt{9 \times 4}}{\sqrt 2}\\\\\\=\dfrac{12+3 \times 2}{\sqrt 2}\\\\\\=\dfrac{18}{\sqrt 2}\\\\\\=\dfrac{18\sqrt 2}{\left(\sqrt 2\right)^2}\\\\\\=\dfrac{18\sqrt 2}2\\\\\\=9\sqrt 2$