Tech A says that packing a wheel bearing assembly can be done by hand with proper results. Tech B says that packing a wheel bearing assembly with a bearing packer will get the proper results. The two statements are right. This is further explained below.
<h3>What is a wheel bearing?</h3>
Generally, the wheel bearing is simply defined as an important component of a vehicle's braking, steering, and suspension systems.
In conclusion, The one-piece hub assembly is located between the drive axle and the brake disc.
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Accepting a good-quality lot would be a <u><em>correct decision.</em></u>
OPTION B "correct decision" is the right answer according to Acceptance Sampling model.
Utilized in quality assurance, acceptance sampling is a statistical method for measuring the reliability of a product or service. It enables a business to ascertain a batch's quality by randomly sampling from it. The standard of quality for the whole set of products will be assumed to be equal to that of the selected sample.
It is impossible for a corporation to constantly test every single one of its goods. It's possible there are too many to inspect efficiently or cheaply. Extensive testing could also compromise the product's quality or render it unmarketable. If a representative sample were tested, the results would be accurate without jeopardizing the rest of the production run.
Acceptance sampling is a method of quality control in which a representative sample of a product batch is tested and its quality is inferred from the results. Acceptance sampling is useful for quality control when implemented properly.
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Answer:
$2,625
Explanation:
Interest is calculated using the formula
I = p x r x t
For Galindo family
I= interest,
P = principal amount : $10,000
r= Interest rate: 7.5 % or 0.075
t= times in years : 3.5 years( 42 months /12)
I= $10,000 x 0.075 x 3.5
I=750 x 3.5
I=$2,625
Answer:
L = 2084.75 W^-0.3
Explanation:
The computation of the demand of the labor is shown below:
At the optimum input
As we know that
MRTS = MPL ÷ MPK = w ÷ r
0.7(K ÷ L)^0.3 ÷ 0.3(L ÷ K)^0.7 = w ÷ 50
7K ÷ 3L = w ÷ 50
K = (3 ÷ 350)wL
Now apply the production function
Q = K^0.3L^0.7
500 = ((3 ÷ 350)wL)^0.3 L^0.7
500 = (3 ÷ 350)^0.3 × w^0.3 × L
L = 2084.75 × w^-0.3.
