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2 years ago

7

I WILL GIVE YOU BRAINLIEST!!!

1 answer:

tino4ka555 [31]2 years ago

4 0

Answer:

To encourage readers to vary the design

Explanation:

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What body part is the metric system based upon? <br> legs <br> arms <br> fingers<br> feet

8_murik_8 [283]

Answer:

arms

Explanation:

because arms can be metric system of our body

3 0

1 year ago

Read 2 more answers

A biochemist carefully measures the molarity of magnesium ion in of cell growth medium to be . Unfortunately, a careless graduat

denis23 [38]

Answer:

760 uM

Explanation:

<em>A biochemist carefully measures the molarity of magnesium ion in 47, mL of cell growth medium to be 97 uM. Unfortunately, a careless graduate student forgets to cover the container of growth medium and a substantial amount of the solvent evaporates. The volume of the cell growth medium falls to 6.0 mL. Calculate the new molarity of magnesium ion in the cell growth medium Be sure your answer has the correct number of significant digits.</em>

The problem here is that the amount of magnesium ion remains the same irrespective of the volume.

Amount of magnesium in the growth medium = <em>molarity x volume</em>

= 97 x $10^{-6}$ x 47 x $10^{-3}$ = 4.559 x $10^{-6}$

Then, the volume reduced to 6.0 mL, the new molarity becomes;

<em>molarity = mole/volume </em>

= 4.559 x $10^{-6}$ /6 x $10^{-3}$ = 7.598333 x $10^{-4}$ M = 759.83333 uM

To the correct number of significant digits = 760 uM

6 0

2 years ago

All BUT one is a quantitative observation. 420 dogs .667 cm big grasshoppers

RSB [31]

Big grasshoppers, because it does not involve a number.

Hope this helps! <3

7 0

2 years ago

According to the data, how much energy would be liberated burning 0.554 kg of olive oil?

nirvana33 [79]

Answer:

2.18×10⁴ kJ are liberated when you burn 0.554 kg of olive oil

Explanation:

The chart indicates that ΔH combustion for the olive oil is 39.31 kJ/g which means that, when you burn 1 g of olive oil, you have 39.31 kJ of heat.

In this case, the mass of olive is 0.554 kg. Let's convert the mass from kg to g → 0.554 kg . 1000 g / 1kg = 554 g

Now, the conversion factor:

554 g . 39.31 kJ / 1g = 2.18×10⁴ kJ

6 0

2 years ago

A solution of the primary standard potassium hydrogen phthalate (KHP), KHC8H4O4 , was prepared by dissolving 0.4877 g of KHP in

Flura [38]

<u>Answer:</u> The concentration of KOH solution is 0.103 M.

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Given mass of KHP = 0.4877 g

Molar mass of KHP = 204.22 g/mol

Putting values in equation 1, we get:

$\text{Moles of KHP}=\frac{0.4877g}{204.22g/mol}=0.0024mol$

The chemical reaction for the reaction of KHP with KOH follows:

$KHC_8H_4O_4(aq.)+KOH\rightarrow K_2C_8H_4O_4(aq.)+H_2O(l)$

By Stoichiometry of the reaction:

1 mole of KHP reacts with 1 mole of KOH.

So, 0.0024 moles of KHP will react with = $\frac{1}{1}\times 0.0024=0.0024mol$ of KOH.

To calculate the molarity of KOH, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}$

We are given:

Moles of KOH = 0.0024 moles

Volume of solution = 23.22 mL = 0.02322L (Conversion factor: 1L = 1000 mL)

Putting values in above equation, we get:

$\text{Molarity of KOH }=\frac{0.0024mol}{0.02322L}=0.103M$

Hence, the molarity of KOH solution is 0.103 M.

6 0

2 years ago