Answer:
50%
Explanation:
This question involves a single gene with two alleles W and w in puppies. According to the question, the genotype of the parent organisms are Ww. In a cross between the two parents i.e. Ww × Ww, the following gametes will be produced by each parent: W and w.
Using these gametes in a punnet square (see attached image), the following genotype of offsprings will be produced: WW, Ww, Ww, ww. Hence, based on this question, the percentage of puppies that would have the same genotype as the parents, Ww are 1/2 × 100% = 50%.
Answer:
Option C
Explanation:
Given ,
A1 allele is carried by % people
Let us assume A1 s dominant genotype
This means
Thus, frequency of allele in the given population is
It is also given that the population is in Hardy-Weinberg equilibrium thus
Frequency of fruit fly with genotype A2A2 will be
As per Hardy-Weinberg's second equation of equilibrium
Hence, option C is correct
Answer:
Nerve cells
Explanation:
Part of the nervous system which is capable of communicating messages to others cells via electrical signals