We are asked to find the probability that a data value in a normal distribution is between a z-score of -1.32 and a z-score of -0.34.
The probability of a data score between two z-scores is given by formula .
Using above formula, we will get:
Now we will use normal distribution table to find probability corresponding to both z-scores as:
Now we will convert into percentage as:
Upon rounding to nearest tenth of percent, we will get:
Therefore, our required probability is 27.4% and option C is the correct choice.
Answer:
Convert from a fraction to a decimal 1/4. 0.25
If the problem is 6r•s•4rt•10rst, then the answer is 240•r^3•s^2•t^2.