Step-by-step explanation:
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Answer:
The required vector parametric equation is given as:
r(t) = <3cost, 3sint>
For 0 ≤ t ≤ 2π
Step-by-step explanation:
Given that
f(x, y) = <2y, -sin(y)>
Since C is a cirlce centered at the origin (0, 0), with radius r = 3, it takes the form
(x - 0)² + (y - 0)² = r²
Which is
x² + y² = 9
Because
cos²β + sin²β = 1
and we want to find a vector parametric equations r(t) for the circle C that starts at the point (3, 0), we can write
x = 3cosβ
y = 3sinβ
So that
x² + y² = 3²cos²β + 3²sin²β
= 9(cos²β + sin²β) = 9
That is
x² + y² = 9
The vector parametric equation r(t) is therefore given as
r(t) = <x(t), y(t)>
= <3cost, 3sint>
For 0 ≤ t ≤ 2π
Step-by-step explanation:
5 - 4 + 7x + 1 = 7x + 2.
If there are no solutions, then it is of the form 7x + c, where c is any real number besides 2.
If there is 1 solution, then it is of the form mx + c, where m is any real number besides 7 and c is any real number.
If there are infinitely many solutions, then it is of the form 7x + 2.
Answer:
Between 0 and 1
Step-by-step explanation:
The given expresion is
Recall that:
We apply this property of exponents to get;
We rewrite to obtain a positive index as:
Therefore the value of the expression is between 0 and 1.