ABCD ≅ FGHJ. Find the measure of the given angles or lengths of the given sides. CD = 2x + 3; HJ = 3x + 2.

1 answer:

3 0

The question asks for the length of CD and HJ. To find those, we need to find a connection between them.

In the given statement, it says ABCD ≅ FGHJ. When we look at the equation, the corresponding letters are equal. For example, angle A is congruent to Angle F. Or BC ≅ GH.

So we know that CD and HJ are congruent.
Set them equal:
$2x + 3 = 3x + 2$
Subtract 2x from both sides:
$3 = x + 2$
Subtract 2 from both sides:
$x = 3$
If x is 3, plug it in:
$3(3) + 2$
Simplify:
$9 + 2 = 11$

So, HJ is 11. And because HJ ≅ CD, CD is 11 too.

You might be interested in

One common factor of two numbers is 40. Another common factor is 10. If both numbers are less than 100, what are the two numbers

Viefleur [7K]

Only two numbers less than 100 have a factor of 40: 40 (1 x 40) and 80 (2 x 40). Since 40 is a factor of both 40 and 80, 10 must also be a factor - indeed, 40 = 4 x 10 and 80 = 8 x 10.

The two number must be 40 and 80.

5 0

2 years ago

Find the sum or difference. Round your answer appropriately. 6.8 L + 5 L

marshall27 [118]

The answer could be 11.8L
If rounded 12L

8 0

2 years ago

Read 2 more answers

2x + 3 = 4x^2<br> completing the square

ch4aika [34]

Answer:

$\frac{1+\sqrt{13} }{4}, \frac{1-\sqrt{13} }{4}$

Step-by-step explanation:

First, make them on one side of the formula in the form of $ax^2+bx+c=0$ which is $4x^{2} -2x-3=0$

Next, insert the corresponding number in the quadratic formula, $\frac{-b+\sqrt{b^{2}-4ac } }{2a} ,\frac{-b-\sqrt{b^{2}-4ac } }{2a}$ , and the answer can be calculated.