2 years ago

What is the inverse of f(x)=x^-9

1 answer:

3 0

$y = \frac{1}{x^9}\\yx^9 = 1\\x^9 = \frac{1}{y}\\x = \sqrt[9]{\frac{1}{y}}\\Therefore, \ f^{-1}(x)=\sqrt[9]{\frac{1}{x}}.$

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Step-by-step explanation:

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2 years ago

I’m not sure how to do this. Plz help and show the work

kramer

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2 years ago