write the equation of a line in slope intercept form that passes through (2 -2) and is parallel to 2x+4y=8

Mathematics

1 answer:

Ne4ueva [31]2 years ago

8 0

Answer:

y= -1/2x-1

Step-by-step explanation:

1) put the equation in y-intercept form to find the slope of the original line 2x+4y=8

y=8/4-2x/4

y=2-1/2x

slope of second line will be -1/2

2) put point into the point-slope form (2,-2)

y-(-2)= -1/2(x-2) now simplify

y+2= -1/2x+2/2

y+2 = -1/2x + 1

y+2-2=-1/2x + 1 -2 ====>>>> y= -1/2x-1

You might be interested in

What is 65% of 60??? PLZZZZZZZZZZ HELP thanks! :)

a_sh-v [17]

All we have to do is multiply them by each other accept we change the percent into a decimal.
65% = 0.65
soooo
0.65 x 65 = 42.25
answer? =42.25
i hope this was helps:)
and don't forget 2
MARK ME BRAINLIEST! :D

4 0

2 years ago

Read 2 more answers

What is 0 + y when y = -11

Mashutka [201]

when y = -11, 0 + y is equal to -11.

the question is asking us to add 0 to the given value of y. the given value of y is -11, so place -11 into 0 + y and you get 0 + -11. since you are adding zero, you are making no changes to the y value, so it stays at -11.

hope this helps and have a great day!

3 0

2 years ago

Read 2 more answers

PLEASE!!!!!!!The adjoining figure shows two circles with the same center. The

Nookie1986 [14]

<h3>Answer:</h3>

$\boxed{\boxed{\pink{\sf \leadsto Hence \ the \ area \ of \ shaded \ region \ is 264 cm^2}}}$

<h3>Step-by-step explanation:</h3>

Here , two circles are given which are concentric. The radius of larger circle is 10cm and that of smaller circle is 4cm . And we need to find thelarea of shaded region.

From the figure it's clear that the area of shaded region will be the difference of areas of two circles.

Let the,

Radius of smaller circle be r .
Radius of smaller circle be r .
Area of shaded region be $\bf Area_{shaded}$

$\bf \implies Area_{Shaded}= Area_{bigger}-Area_{smaller} \\\\\bf\implies Area_{Shaded} = \pi R^2 - \pi r^2 \\\\\bf\implies Area_{shaded} = \pi ( R^2-r^2) \\\\\bf\implies Area_{shaded} = \pi [ (10cm)^2 - (4cm)^2] \\\\\bf\implies Area_{shaded} = \pi [ 100cm^2-16cm^2] \\\\\bf\implies Area_{shaded} = \pi \times 84cm^2 \\\\\bf\implies Area_{shaded} = \dfrac{22}{7}\times 84cm^2 \\\\\bf\implies \boxed{\red{\bf Area_{shaded} = 264 cm^2 }}$